32y^4-50y^2=

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Solution for 32y^4-50y^2= equation:


Simplifying
32y4 + -50y2 = 0

Reorder the terms:
-50y2 + 32y4 = 0

Solving
-50y2 + 32y4 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2y2'.
2y2(-25 + 16y2) = 0

Factor a difference between two squares.
2y2((5 + 4y)(-5 + 4y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(5 + 4y)' equal to zero and attempt to solve: Simplifying 5 + 4y = 0 Solving 5 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 4y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 4y = 0 + -5 4y = 0 + -5 Combine like terms: 0 + -5 = -5 4y = -5 Divide each side by '4'. y = -1.25 Simplifying y = -1.25

Subproblem 3

Set the factor '(-5 + 4y)' equal to zero and attempt to solve: Simplifying -5 + 4y = 0 Solving -5 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + 4y = 0 + 5 Combine like terms: -5 + 5 = 0 0 + 4y = 0 + 5 4y = 0 + 5 Combine like terms: 0 + 5 = 5 4y = 5 Divide each side by '4'. y = 1.25 Simplifying y = 1.25

Solution

y = {0, -1.25, 1.25}

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